Equation of circle second quardrant : Equation of a circle of radius < a > and lying in the second quardrant such as it is tangent to both the axes.

The required circle is shown in the adjoint figure . the coordinte of the centre are C ( – a , a ).

Equation of the required circle is

[ x – ( – a ) ] ² + [ y – a ] ² = a ²

Solvining sins – × – = +

⇒ [ x + a ] ² + [ y – a ] ² = a ²

⇒ x ² + 2 ax + a ² + y ² – 2ay + a ² – a ² = 0

⇒ x ² + y ² + 2 a x – 2a y + a ² = 0

This is the required equation of circle in second quardrant.

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